49 lines
2.9 KiB
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49 lines
2.9 KiB
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<!-- Common Lisp HyperSpec (TM), version 7.0 generated by Kent M. Pitman on Mon, 11-Apr-2005 2:31am EDT -->
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<TITLE>CLHS: Section 2.4.4.2.5</TITLE>
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<H1><A REV=MADE HREF="http://www.lispworks.com/"><IMG WIDTH=80 HEIGHT=65 ALT="[LISPWORKS]" SRC="../Graphics/LWSmall.gif" ALIGN=Bottom></A><A REL=TOP HREF="../Front/index.htm"><IMG WIDTH=237 HEIGHT=65 ALT="[Common Lisp HyperSpec (TM)]" SRC="../Graphics/CLHS_Sm.gif" ALIGN=Bottom></A> <A REL=PREV HREF="02_ddbd.htm"><IMG WIDTH=40 HEIGHT=40 ALT="[Previous]" SRC="../Graphics/Prev.gif" ALIGN=Bottom></A><A REL=UP HREF="02_ddb.htm"><IMG WIDTH=40 HEIGHT=40 ALT="[Up]" SRC="../Graphics/Up.gif" ALIGN=Bottom></A><A REL=NEXT HREF="02_de.htm"><IMG WIDTH=40 HEIGHT=40 ALT="[Next]" SRC="../Graphics/Next.gif" ALIGN=Bottom></A></H1>
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<H2>
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2.4.4.2.5 Examples of Style for Semicolon</H2> <P>
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<PRE>
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;;;; Math Utilities
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;;; FIB computes the the Fibonacci function in the traditional
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;;; recursive way.
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(defun fib (n)
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(check-type n integer)
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;; At this point we're sure we have an integer argument.
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;; Now we can get down to some serious computation.
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(cond ((< n 0)
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;; Hey, this is just supposed to be a simple example.
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;; Did you really expect me to handle the general case?
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(error "FIB got ~D as an argument." n))
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((< n 2) n) ;fib[0]=0 and fib[1]=1
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;; The cheap cases didn't work.
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;; Nothing more to do but recurse.
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(t (+ (fib (- n 1)) ;The traditional formula
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(fib (- n 2)))))) ; is fib[n-1]+fib[n-2].
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</PRE>
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</TT> <P>
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